C Program to Print Elements of Array using Pointers

The following program to Print Elements of Array using Pointers with simple code with examples.

The C pointer is a variable whose value is the address of another variable, i.e., direct address of the memory location. Like any variable or constant, you must declare a pointer before using it to store any variable address. The general form of a pointer variable declaration as follow.

type *var-name;

Here, type is the pointer’s base type; it must be a valid C data type and var-name is the name of the pointer variable. The asterisk * used to declare a pointer is the same asterisk used for multiplication. However, in this statement the asterisk is being used to designate a variable as a pointer.

Every variable is a memory location and every memory location has its address defined which can be accessed using ampersand (&) operator, which denotes an address in memory.

• We define a pointer variable, int *p
• to assign the address of a variable to a pointer p=&x, x is an integer variable
• Finally access the value at the address available in the pointer variable. v=*p

Save program in a file, Compile program, debug errors,

Execute or Run program with necessary inputs. Verify the outputs obtained.

How it works?

Step1: start

Step2: Read array a[] with n elements

Step 3: initialize pointer p=&a[0] [or p=a]

Step 4: if i<n go to next step otherwise go to step 7

Step 5: print *(p+i)

Step 6: i=i+1 go to step 4

Step 7: stop

Example: C Program to Print Elements of Array using Pointers

Program to print the elements of array using pointers*
#include<stdio.h>
main()
{
int a[5]={5,4,6,8,9};
int *p=&a[0];
int i;
clrscr();
for(i=0;i<5;i++)
printf("%d ",*(p+i));
getch();
}

Output

5 4 6 8 9

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